(x)=4x^2-484

Solution for (x)=4x^2-484 equation:

(x)=4x^2-484

We move all terms to the left:

(x)-(4x^2-484)=0

We get rid of parentheses

-4x^2+x+484=0

a = -4; b = 1; c = +484;
Δ = b2-4ac
Δ = 12-4·(-4)·484
Δ = 7745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{7745}}{2*-4}=\frac{-1-\sqrt{7745}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{7745}}{2*-4}=\frac{-1+\sqrt{7745}}{-8}
$